Introduction :
The reaction of the colligative properties in the vapour pressure of solvent is given as:
In a solution colligative properties containing several non volatile solutions, the lowering of the vapour pressure depends sum of the mole fraction of different solutions.
`(p_(1)^(0)-p_(1))/(p_(1)^(0))` =`(n_(2))/(n_(1)+n_(2))`
The vapour pressure of solution decrease when a non volatile solution
is added to a volation solvent. There are many properties of solution
which are connected with this decreasing of vapour pressure. These are
the relatively of vapour pressure of the solvent, depression of freezing
points of the solvent. Elevation of the boiling point of the solvent,
osmotic pressure of the solution. Everyone these of the property depend
on the numeral of solute particle irrespective of their environment
relative.
Relative lowering of vapour pressure:
In colligative properties and determination of molar mass, the vapour
pressure of a solvent in solution is less than that of the pure solvent.
Raoult recognized that the lower of vapour pressure depends simply on
the concentration of the solute particles and it is dependent of their
individuality.
`p_(1)=x_(1)p_(1)^(0)`
The reaction of the colligative properties in the vapour pressure of solvent is given as:
`Deltap_(1)=p_(1)^(0)-p_(1)=p_(1)^(0)-p_(1)^(0)x_(1)`
=`p_(1)^(0)(1-x_(2))`
In a solution colligative properties containing several non volatile solutions, the lowering of the vapour pressure depends sum of the mole fraction of different solutions.
`(Deltap_(1))/(p_(1)^(0))` =`(p_(1^(0))-p_(1))/(p_(1)^(0))` =`x_(2)`
The expression on the left hand side of the equation as mentioned
earlier is called relative lowering of vapour force and is equal to the
mole division of the solution of the colligative properties. The above
equation can be determinations as:
`(p_(1)^(0)-p_(1))/(p_(1)^(0))` =`(n_(2))/(n_(1)+n_(2))`
Here n1 and n2 are the number of mole of solvent and solute respectively present in the solution.
For dilute solution n2<<n1 hence neglection n2 in the denominator we have
For dilute solution n2<<n1 hence neglection n2 in the denominator we have
`(p_(1)^(0)-p_(1))/(p_(1)^(0))` =`(w_(2)xxM_(1))/(M_(2)xxW_(1))`
Here w1 and w2 are the mass and M1 and M2 are the molar mass of the solvent and solute correspondingly.
It is very helpful for students
ReplyDelete